matematik

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geometri

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arealer

\ hexagon

Cirkel
$$\textbf{Areal af et hexagon}$$ $$A = \frac{1}{4} · 6 · b^2 · \frac{\cos\big(\frac{\pi}{6}\big)}{\sin\big(\frac{\pi}{6}\big)} $$
$$\textbf{Hexagonets perimeter}$$ $$P = 6 · b $$